-3x=1200+2x^2

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Solution for -3x=1200+2x^2 equation:



-3x=1200+2x^2
We move all terms to the left:
-3x-(1200+2x^2)=0
We get rid of parentheses
-2x^2-3x-1200=0
a = -2; b = -3; c = -1200;
Δ = b2-4ac
Δ = -32-4·(-2)·(-1200)
Δ = -9591
Delta is less than zero, so there is no solution for the equation

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